Cube Depot

Yes. I have seen this parity occur in the last 3 solves I did on this beast. I hunted down some sort of algorithm to help me and it's in here. l (D¹)' L'' (R' F R f R' F' R f') L2 (D¹) l' b' (D²) B2 (r' F R' F' r F R F') B'' (D²)' b Very large, but one of the quickest ways.

Posted by CubesAndIllusions on June 25, 2012 at 12:29 PM

742 Views